Answer
$U_3 = 0.0188~J$
Work Step by Step
In part (b), we found that $V_3 = 50.0~V$
We can find $U_3$:
$U_3 = \frac{1}{2}C_3~V_3^2$
$U_3 = \frac{1}{2}(15.0\times 10^{-6} F)(50.0~V)^2$
$U_3 = 0.0188~J$
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