Answer
$V_3 = 50.0~V$
Work Step by Step
In part (a), we found that $q_3 = 750~\mu C$
We can find $V_3$:
$V_3 = \frac{q_3}{C_3}$
$V_3 = \frac{750~\mu C}{15.0~\mu F}$
$V_3 = 50.0~V$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 25 - Capacitance - Problems - Page 742: 38b
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