Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 25 - Capacitance - Problems - Page 742: 37d

Answer

$Work = 7.48\times 10^{-11}~J$

Work Step by Step

In part (b), we found that the initial stored energy is $U_i = 4.52\times 10^{-11}~J$ In part (c), we found that the final stored energy is $U_f = 1.20\times 10^{-10}~J$ We can find the work required to separate the plates: $Work = \Delta U$ $Work = U_f- U_i$ $Work = (1.20\times 10^{-10}~J)- (4.52\times 10^{-11}~J)$ $Work = (12.0\times 10^{-11}~J)- (4.52\times 10^{-11}~J)$ $Work = 7.48\times 10^{-11}~J$
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