Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 6 - Review - Exercises - Page 529: 64

Answer

$\frac{\sqrt {55}}{8}$

Work Step by Step

Step 1. Let $u=cos^{-1}\frac{3}{8}$, we have$ cos(u)=\frac{3}{8}$ The range of inverse cosine is $[0,\pi]$, thus $0\lt u\lt \frac{\pi}{2}$ Step 2. With the results above and use the Pythagorean Identity $sin^2u=1-cos^2u=1-\frac{9}{64}=\frac{55}{64}$ Step 3. $sin(cos^{-1}\frac{3}{8})=sin(u)=\frac{\sqrt {55}}{8}$
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