Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 6 - Review - Exercises - Page 529: 77

Answer

$\approx 80.4^0$

Work Step by Step

From the law of cosines $120^{2}=100^{2}+85^{2}-2\times 100\times 85\times \cos \theta \Rightarrow 17000\cos \theta =100^{2}+85^{2}-120^{2}=2825$ $\Rightarrow \cos \theta =\dfrac {2825}{17000}\approx 0.167\Rightarrow \theta \approx \cos ^{-1}\left( 0.167\right) \approx 80.4^0$
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