Answer
$\tan \theta =\dfrac {\sin \theta }{\cos \theta }=\dfrac {\sqrt {1-\cos ^{2}\theta }}{\cos \theta }$
Work Step by Step
$\tan \theta =\dfrac {\sin \theta }{\cos \theta }=\dfrac {\sqrt {1-\cos ^{2}\theta }}{\cos \theta }$
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 6 - Review - Exercises - Page 529: 49
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