Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 6 - Review - Exercises - Page 529: 71

Answer

$\approx 110.03$

Work Step by Step

From the law of cosines $x^{2}=100^2+210^{2}-2\times 100\times 210 \times cos40^0\Rightarrow x=\sqrt {1002+210^{2}-2\times 100\times 210\cos 40^0}\approx 110.03$
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