Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 6 - Review - Exercises - Page 529: 74

Answer

$\approx 3.43 $

Work Step by Step

From the law of cosines $6^{2}=4^{2}+x^{2}-2\times 4\times x\times \cos 110\Rightarrow x^{2}-x\times \left( 8\cos 110\right) +\left( 4^{2}-6^{2}\right) =0$ $x^{2}-8\cos 110\times x-20=0\Rightarrow x=\dfrac {8\cos 110\pm \sqrt {\left( 8\cos 110\right) ^{2}+4\times 20}}{2}\approx \dfrac {8\times \left( -0.342\right) \pm \sqrt {\left( 8\times \left( -0.342\right) \right) ^{2}+80}}{2} \approx 3.43$
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