Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 6 - Review - Exercises - Page 529: 75

Answer

$ \approx 54.1^0$

Work Step by Step

From the law of sines $\dfrac {23}{\sin \theta }=\dfrac {12}{\sin 25}\Rightarrow \sin \theta =\dfrac {23\times \sin 25}{12}\approx 0.81\Rightarrow \theta \approx \arcsin ^{-1}\left( 0.81\right) \approx 54.1$
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