Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 6 - Review - Exercises - Page 529: 68

Answer

$\theta =\tan ^{-1}\left( \dfrac {x}{2}\right) $

Work Step by Step

Lets apply law of sines to this right triangle In a right triangle if one internal angle is $\theta $ other angle will be $\alpha =180-90-\theta =90-\theta $ (sum of internal angles of triangle is 180) $\dfrac {x}{\sin \theta }=\dfrac {2}{\sin \left( 90-\theta \right) }=\dfrac {2}{\cos \theta }\Rightarrow \tan \theta =\dfrac {x}{2}\Rightarrow \theta =\tan ^{-1}\left( \dfrac {x}{2}\right) $
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