Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 6 - Review - Exercises - Page 529: 36

Answer

$-\dfrac {\sqrt {3}}{2}$

Work Step by Step

$\cos \left( \dfrac {5\pi }{6}\right) =\cos \left( \pi -\dfrac {\pi }{6}\right) =\cos \pi \cos \dfrac {\pi }{6}+\sin \pi \sin \dfrac {\pi }{6}=\left( -1\right) \times \cos \dfrac {\pi }{6}+0\times \sin \dfrac {\pi }{6}=-\cos \dfrac {\pi }{6}=-\dfrac {\sqrt {3}}{2}$
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