Answer
$\sin \theta = -\frac{9}{41}$
$\cos \theta = \frac{40}{41}$
$\tan \theta = -\frac{9}{40}$
$\cot \theta = -\frac{40}{9} $
Work Step by Step
We have the following information :
$\sec \theta = \frac{r}{x} = \frac{41}{40}$
$\csc \theta = \frac{r}{y} = -\frac{41}{9}$
It's clear, that :
$x=40$
$y=-9$
$r=41$
So, the remaining $4$ trigonometric functions will be :
$\sin \theta = \frac{y}{r} = -\frac{9}{41}$
$\cos \theta = \frac{x}{r} = \frac{40}{41}$
$\tan \theta = \frac{y}{x} = -\frac{9}{40}$
$\cot \theta = \frac{x}{y} = -\frac{40}{9} $
