Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 6 - Review - Exercises - Page 529: 72

Answer

$\approx77.82$

Work Step by Step

From the law of cosines $20^{2}+x^{2}-2\times 20\times x\times \cos 60^0=70^{2}\Rightarrow x^{2}-20x+400=4900\Rightarrow x^{2}-20x-4500=0$ $\Rightarrow x=\dfrac {20\pm \sqrt {20^{2}+4\times 1\times 4500}}{2}=\dfrac {20\pm \sqrt {18400}}{2}\approx 77.82$
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