Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 6 - Review - Exercises - Page 529: 69

Answer

$x\approx 5.94$

Work Step by Step

First lets find $\angle B $ $\angle A+\angle B+\angle C=180^0\Rightarrow 30^0+80^0+\angle B\Rightarrow \angle B=180^0-\left( 80^0+30^0\right) =70^0$ From the law of sines $\dfrac {x}{\sin 30}=\dfrac {10}{\sin \angle B}\Rightarrow \dfrac {x}{\dfrac {1}{2}}=\dfrac {10}{\sin 70}\Rightarrow x=\dfrac {5}{\sin 70}\approx 5.94$
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