Answer
center $(1,0)$, foci $(1,-2\sqrt 2),(1,2\sqrt 2)$, vertices $(1,-3),(1,3)$
See graph.
Work Step by Step
1. $9x^2+y^2-18x=0\Longrightarrow 9(x-1)^2+(y)^2=9$ or $\frac{(x-1)^2}{1}+\frac{(y)^2}{9}=1$,
2. we can find center $(1,0)$ with a vertical major axis, $a=3, b=1$, $c=\sqrt {a^2-b^2}=\sqrt {9-1}=2\sqrt 2$,
3. thus foci $(1,\pm2\sqrt 2)$ or $(1,-2\sqrt 2),(1,2\sqrt 2)$, vertices $(1,\pm3)$ or $(1,-3),(1,3)$
4. See graph.
