Answer
$\frac{(x)^2}{4}+\frac{(y-1)^2}{1}=1$
Work Step by Step
Based on the given graph, we have center $(0,1)$ with a horizontal major axis, $a=2, b=1$, thus $c=\sqrt {a^2-b^2}=\sqrt {4-1}=\sqrt {3}$, and $\frac{(x)^2}{4}+\frac{(y-1)^2}{1}=1$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 9 - Analytic Geometry - Section 9.3 The Ellipse - 9.3 Assess Your Understanding - Page 677: 42
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