Answer
vertices $(-3,0),(3,0)$, foci $(-\sqrt {5},0),(\sqrt {5},0)$.
See graph.
Work Step by Step
1. Based on the given equation $\frac{x^2}{9}+\frac{y^2}{4}=1$, we have $a=3, b=2$ with center $(0,0)$ and a horizontal major axis, thus $c=\sqrt {a^2-b^2}=\sqrt {9-4}=\sqrt {5}$, vertices $(-3,0),(3,0)$, foci $(-\sqrt {5},0),(\sqrt {5},0)$.
2. See graph.
