Answer
vertices $(0,-4),(0,4)$, foci $(0,-\sqrt {15}),(0,\sqrt {15})$.
See graph.
Work Step by Step
1. Based on the given equation $\frac{x^2}{1}+\frac{y^2}{16}=1$, we have $a=4, b=1$ with center $(0,0)$ and a vertical major axis, thus $c=\sqrt {a^2-b^2}=\sqrt {16-1}=\sqrt {15}$, vertices $(0,-4),(0,4)$, foci $(0,-\sqrt {15}),(0,\sqrt {15})$.
2. See graph.
