Chapter 9 - Analytic Geometry - Section 9.3 The Ellipse - 9.3 Assess Your Understanding - Page 677: 34

$\frac{x^2}{48}+\frac{y^2}{64}=1$ See graph.

1. Based on the given conditions, we have $a=8, c=4$, center $(0,0)$ with a vertical major axis, thus $b=\sqrt {a^2-c^2}=\sqrt {64-16}=4\sqrt 3$, and $\frac{x^2}{48}+\frac{y^2}{64}=1$ 2. See graph.