Answer
vertices $(-3\sqrt 2,0),(3\sqrt 2,0)$, foci $(-4,0),(4,0)$.
See graph.
Work Step by Step
1. Based on the given equation, we have $\frac{x^2}{18}+\frac{y^2}{2}=1$, with $a=\sqrt {18}=3\sqrt 2, b=\sqrt 2$, center $(0,0)$ and a horizontal major axis, thus $c=\sqrt {a^2-b^2}=\sqrt {18-2}=4$, vertices $(-3\sqrt 2,0),(3\sqrt 2,0)$, foci $(-4,0),(4,0)$.
2. See graph.
