Answer
$\frac{(x+1)^2}{4}+\frac{(y-1)^2}{1}=1$
Work Step by Step
Based on the given graph, we have center $-1,1)$ with a horizontal major axis, $a=1+1=2, b=1$, thus $c=\sqrt {a^2-b^2}=\sqrt {4-1}=\sqrt {3}$, and $\frac{(x+1)^2}{4}+\frac{(y-1)^2}{1}=1$
