Answer
vertices $(-2\sqrt 2,0),(2\sqrt 2,0)$, foci $(-\sqrt 6,0),(\sqrt 6,0)$.
See graph.
Work Step by Step
1. Based on the given equation, we have $\frac{x^2}{8}+\frac{y^2}{2}=1$, with $a=\sqrt {8}=2\sqrt 2, b=\sqrt 2$, center $(0,0)$ and a horizontal major axis, thus $c=\sqrt {a^2-b^2}=\sqrt {8-2}=\sqrt 6$, vertices $(-2\sqrt 2,0),(2\sqrt 2,0)$, foci $(-\sqrt 6,0),(\sqrt 6,0)$.
2. See graph.
