Answer
vertices $(0,-3),(0,3)$, foci $(0,-\sqrt 5),(0,\sqrt 5)$.
See graph.
Work Step by Step
1. Based on the given equation, we have $\frac{x^2}{4}+\frac{y^2}{9}=1$, with $a=\sqrt {9}=3, b=\sqrt 4=2$, center $(0,0)$ and a vertical major axis, thus $c=\sqrt {a^2-b^2}=\sqrt {9-4}=\sqrt 5$, vertices $(0,-3),(0,3)$, foci $(0,-\sqrt 5),(0,\sqrt 5)$.
2. See graph.
