Answer
$\frac{x^2}{9}+\frac{y^2}{8}=1$
See graph.
Work Step by Step
1. Based on the given conditions, we have $a=3, c=1$, center $(0,0)$ with a horizontal major axis, thus $b=\sqrt {a^2-c^2}=\sqrt {9-1}=2\sqrt 2$, and $\frac{x^2}{9}+\frac{y^2}{8}=1$
2. See graph.
