Answer
$\frac{(x+1)^2}{1}+\frac{(y+1)^2}{4}=1$
Work Step by Step
Based on the given graph, we have center $-1,-1)$ with a vertical major axis, $a=1+1=2, b=1$, thus $c=\sqrt {a^2-b^2}=\sqrt {4-1}=\sqrt {3}$, and $\frac{(x+1)^2}{1}+\frac{(y+1)^2}{4}=1$
