Answer
$\frac{x^2}{4}+\frac{y^2}{13}=1$
See graph.
Work Step by Step
1. Based on the given conditions, we have $c=3, b=2$, center $(0,0)$ with a vertical major axis, thus $a=\sqrt {b^2+c^2}=\sqrt {4+9}=\sqrt {13}$, and $\frac{x^2}{4}+\frac{y^2}{13}=1$
2. See graph.
