Answer
$\frac{\pi}{4}$.
Work Step by Step
Let $sec^{-1}\sqrt 2=t$, we have $sec(t)=\sqrt 2$ and $cos(t)=\frac{1}{sec(t)}=\frac{\sqrt 2}{2}$. Thus $t=\frac{\pi}{4}$.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 6 - Analytic Trigonometry - Chapter Review - Review Exercises - Page 527: 7
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