Answer
$-\frac{4}{3}$
Work Step by Step
Let $sin^{-1}(-\frac{4}{5})=t$ (t in quadrant IV), we have $sin(t)=-\frac{4}{5}$, thus $tan(t)=-\frac{4}{3}$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 6 - Analytic Trigonometry - Chapter Review - Review Exercises - Page 527: 23
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