Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 6 - Analytic Trigonometry - Chapter Review - Review Exercises - Page 527: 19

Answer

$\pi$

Work Step by Step

Use the properties of an inverse function, $cos^{-1}(tan(\frac{3\pi}{4}))=cos^{-1}(-tan(\frac{\pi}{4}))=cos^{-1}(-1)=\pi$
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