Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 6 - Analytic Trigonometry - Chapter Review - Review Exercises - Page 527: 20

Answer

$ -\sqrt 3$

Work Step by Step

$tan(sin^{-1}(-\frac{\sqrt 3}{2}))=tan(-\frac{\pi}{3})=-\sqrt 3$
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