Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 6 - Analytic Trigonometry - Chapter Review - Review Exercises - Page 527: 1

Answer

$\dfrac{\pi}{2}$

Work Step by Step

From the unit circle, we know that $\sin (\dfrac{\pi}{2})=1$ Thus, the inverse of the sine function can be expressed as: $\sin^{-1}(1)=\dfrac{\pi}{2}$
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