Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 6 - Analytic Trigonometry - Chapter Review - Review Exercises - Page 527: 33

Answer

See below.

Work Step by Step

$LHS=\frac{csc\theta}{1+csc\theta} =\frac{1/sin\theta}{1+1/sin\theta} =\frac{1}{sin\theta+1}$ $RHS=\frac{1-sin\theta}{cos^2\theta} =\frac{1-sin\theta}{1-sin^2\theta} =\frac{1}{1+sin\theta} =LHS$
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