Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 6 - Analytic Trigonometry - Chapter Review - Review Exercises - Page 527: 39

Answer

See below.

Work Step by Step

$LHS=(1+cos\theta)tan\frac{\theta}{2}=(1+cos\theta)\times\frac{sin\theta}{1+cos\theta}=sin\theta =RHS$
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