Answer
$\frac{2\sqrt 3}{3}$
Work Step by Step
$sec(tan^{-1}(\frac{\sqrt 3}{3}))=sec(\frac{\pi}{6})=\frac{1}{cos(\frac{\pi}{6})}=\frac{2\sqrt 3}{3}$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 6 - Analytic Trigonometry - Chapter Review - Review Exercises - Page 527: 21
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