Answer
See below.
Work Step by Step
$LHS=sin^2\theta(1+cot^2\theta)=sin^2\theta(csc^2\theta)=sin^2\theta(\frac{1}{sin^2\theta})=1=RHS$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 6 - Analytic Trigonometry - Chapter Review - Review Exercises - Page 527: 29
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