Answer
See below.
Work Step by Step
$LHS=5cos^2\theta+3sin^2\theta=(3+2)cos^2\theta+3sin^2\theta=3cos^2\theta+3sin^2\theta+2cos^2\theta=3+2cos^2\theta=RHS$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 6 - Analytic Trigonometry - Chapter Review - Review Exercises - Page 527: 30
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