Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 6 - Analytic Trigonometry - Chapter Review - Review Exercises - Page 527: 35

Answer

See below.

Work Step by Step

$LHS=\frac{1-sin\theta}{sec\theta}=cos\theta(1-sin\theta)$ $RHS=\frac{cos^3\theta}{1+sin\theta} =\frac{cos\theta(cos^2\theta)}{1+sin\theta} =\frac{cos\theta(1-sin^2\theta)}{1+sin\theta} =cos\theta(1-sin\theta) =LHS$
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