Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 11 - Further Topics in Algebra - 11.1 Sequences and Series - 11.1 Exercises - Page 1014: 54



Work Step by Step

$\sum_{i=1}^4(i^4-i^3)$ $=(1^4-1^3)+(2^4-2^3)+(3^4-3^3)+(4^4-4^3)$ $=0+8+54+192$ $=\boxed{254}$
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