#### Answer

$343$

#### Work Step by Step

$\sum_{i=1}^5 (3^i-4)$
$=(3^1-4)+(3^2-4)+(3^3-4)+(3^4-4)+(3^5-4)$
$=-1+5+23+77+239$
$=343$

Published by
Pearson

ISBN 10:
013421742X

ISBN 13:
978-0-13421-742-0

$343$

$\sum_{i=1}^5 (3^i-4)$
$=(3^1-4)+(3^2-4)+(3^3-4)+(3^4-4)+(3^5-4)$
$=-1+5+23+77+239$
$=343$

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