Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 11 - Further Topics in Algebra - 11.1 Sequences and Series - 11.1 Exercises - Page 1014: 47


$\dfrac {728}{9}=80\dfrac {8}{9}$

Work Step by Step

$\sum ^{3}_{i=-2}2\left( 3\right) ^{i}=2\times 3^{-2}+2\times 3^{-1}+2\times 3^{0}+2\times 3^{1}+2\times 3^{2}+2\times 3^{3}=\dfrac {728}{9}=80\dfrac {8}{9}$
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