Precalculus (6th Edition)

Published by Pearson

Chapter 11 - Further Topics in Algebra - 11.1 Sequences and Series - 11.1 Exercises: 12

Answer

$A_{1}=3;a_{2}=9;a_{3}=15;a_{4}=21;a_{5}=27$

Work Step by Step

$a_{1}=6\times 1-3=3;$ $a_{2}=6\times 2-3=9;$ $a_{3}=6\times 3-3=15;$ $a_{4}=6\times 4-3=21;$ $a_{5}=6\times 5-3=27$

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