Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 11 - Further Topics in Algebra - 11.1 Sequences and Series - 11.1 Exercises - Page 1014: 52



Work Step by Step

$\sum_{i=1}^4[(-2)^i-3]$ $=[(-2)^1-3]+[(-2)^2-3]+[(-2)^3-3]+[(-2)^4-3]$ $=-5+1+(-11)+13$ $\boxed{=-2}$
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