Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 11 - Further Topics in Algebra - 11.1 Sequences and Series - 11.1 Exercises: 39

Answer

$\dfrac {25}{12}$

Work Step by Step

$\sum ^{4}_{j=1}j^{-1}=\dfrac {1}{1}+\dfrac {1}{2}+\dfrac {1}{3}+\dfrac {1}{4}=\dfrac {25}{12}$
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