Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 11 - Further Topics in Algebra - 11.1 Sequences and Series - 11.1 Exercises - Page 1014: 45



Work Step by Step

$\sum ^{5}_{i=2}\left( 6-3i\right) =\sum ^{5}_{i=2}\dfrac {63}{}\sum ^{5}_{i=2}i=\sum ^{4}_{i=1}\dfrac {63}{}\sum ^{5}_{i=2}i=4\times 6-3\left( 2+3+4+5\right) =-18$
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