Answer
$-18$
Work Step by Step
$\sum ^{5}_{i=2}\left( 6-3i\right) =\sum ^{5}_{i=2}\dfrac {63}{}\sum ^{5}_{i=2}i=\sum ^{4}_{i=1}\dfrac {63}{}\sum ^{5}_{i=2}i=4\times 6-3\left( 2+3+4+5\right) =-18$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 11 - Further Topics in Algebra - 11.1 Sequences and Series - 11.1 Exercises - Page 1014: 45
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