Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 11 - Further Topics in Algebra - 11.1 Sequences and Series - 11.1 Exercises - Page 1014: 22


$a_{1}=7;$ $a_{2}=7;$ $a_{3}=9;$ $a_{4}=13;$ $a_{5}=19$

Work Step by Step

$a_{1}=\dfrac {1^{3}+27}{1+3}=7;$ $a_{2}=\dfrac {2^{3}+27}{2+3}=7;$ $a_{3}=\dfrac {3^{3}+27}{3+3}=9;$ $a_{4}=\dfrac {4^{3}+27}{4+3}=13;$ $a_{5}=\dfrac {5^{3}+27}{5+3}=19$
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