#### Answer

$\dfrac {75}{2}$

#### Work Step by Step

$\sum ^{2}_{i=-1}5\left( 2\right) ^{i}=5\left( 2^{-1}+2^{0}+2^{1}+2^{2}\right) =\dfrac {75}{2}$

Published by
Pearson

ISBN 10:
013421742X

ISBN 13:
978-0-13421-742-0

$\dfrac {75}{2}$

$\sum ^{2}_{i=-1}5\left( 2\right) ^{i}=5\left( 2^{-1}+2^{0}+2^{1}+2^{2}\right) =\dfrac {75}{2}$

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