Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 11 - Further Topics in Algebra - 11.1 Sequences and Series - 11.1 Exercises: 50

Answer

$176$

Work Step by Step

$\sum_{i=3}^6 (2i^2+1)$ $=(2*3^2+1)+(2*4^2+1)+(2*5^2+1)+(2*6^2+1)$ $=19+33+51+73$ $=176$
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