Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 11 - Further Topics in Algebra - 11.1 Sequences and Series - 11.1 Exercises: 38

Answer

$51$

Work Step by Step

$\sum ^{6}_{i=1}\left( 3i-2\right) =3\sum ^{6}_{i=1}i-\sum ^{6}_{i=1}2=\dfrac {3\times 6\times \left( 6+1\right) }{2}-6\times 2=51$
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