Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 11 - Further Topics in Algebra - 11.1 Sequences and Series - 11.1 Exercises: 49

Answer

$28$

Work Step by Step

$\sum ^{5}_{i=-1}\left( i^{2}-2i\right) =\left( \left( -1\right) ^{2}-2\left( -1\right) \right) +\left( 0^{2}-2\times 0\right) +\left( 1^{2}-2\times 1\right) +\left( 2^{2}-2\times 2\right) +\left( 3^{2}-2\times 3\right) +\left( 4^{2}-2\times 4\right) +\left( 5^{2}-2\times 5\right) =28$
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