Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Section 9.3 - The Parabola - Exercise Set - Page 997: 67


See figure; no solution.

Work Step by Step

Step 1. Graph the given equations $\begin{cases} x=(y+2)^2-1 \\(x-2)^2+(y+2)^2=1 \end{cases}$ as shown in the figure. Step 2. We can not identify any intersection points, so the system has no solution.
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